Section 2.6 10, 12, 14, 16 [ATTACH=full]486[/ATTACH] Q. 10 The numerator is 1, which can be expressed as 1•x^0. The degree of the numerator is smaller than the degree of the denominator. The horizontal asymptote is the line y = 0. Q. 12 The degree of the numerator = degree of denominator. The horizontal asymptote is -7/2 for this question. Q. 14 The degree of the numerator > degree of denominator. So, no horizontal asymptote. Q. 16 The degree of the numerator = degree of the denominator. So, the horizontal asymptote is -4/1 or simply -4. You say?